SOLUTION: in the ellipse x2/30 + y2/24 = 1 find the point which is 5 uniits distanced from the minor axis

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Question 834383: in the ellipse x2/30 + y2/24 = 1 find the point which is 5 uniits distanced from the minor axis
Answer by lwsshak3(11628) About Me  (Show Source):
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in the ellipse x2/30 + y2/24 = 1 find the point which is 5 uniits distanced from the minor axis.
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This is an ellipse with horizontal major axis.
Minor axis is on the y-axis.
At 5 units from the minor axis, x=5 or x=-5
solving for y:
x%5E2%2F30%2By%5E2%2F24=1
5%5E2%2F30%2By%5E2%2F24=1
25%2F30%2By%5E2%2F24=1
LCD:30*24=720
25%2F30%2By%5E2%2F24=1
600+30y^2=720
30y^2=120
y^2=4
y=±√4=±2
Points which are 5 units distanced from the minor axis: (5,2),(5,-2),(-5,2),(-5,-2)