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Question 820685: Change to standard equation for a circle.((x-x1)^2+(y-y1)^2=r^2) Find the center and radius. x^2-6x+9+y^2-4x+4=16
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Change to standard equation for a circle.((x-x1)^2+(y-y1)^2=r^2) Find the center and radius. x^2-6x+9+y^2-4x+4=16
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Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius.
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x^2-6x+9+y^2-4x+4=16
x^2-10x+y^2=3
complete the square:
(x^2-10x+25)+y^2=3+25
(x-5)^2+y^2=28
center:(5,0)
radius: √28≈5.29
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