SOLUTION: discribe and sketch the conic x^2+4y+8x+4=0

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Question 811490: discribe and sketch the conic x^2+4y+8x+4=0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
discribe and sketch the conic x^2+4y+8x+4=0
x^2+8x+16 = -4y-4+16
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(x + 4)^2 = -4y + 12
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-4(y-3) = (x+4)^2
y = (-1/4)(x+4)^2 + 3
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graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C%28-1%2F4%29%28x%2B4%29%5E2%2B3%29
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vertex at (-4,3)
parabola opening downward
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Cheers,
Stan H.
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