SOLUTION: Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y

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Question 789490: Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y
Answer by lwsshak3(11628) About Me  (Show Source):
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Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y
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This is an equation of a parabola that opens down with vertex at the origin.
Its basic form: x^2=-4py
For given parabola:
axis of symmetry: x=0
4p=2
p=1/2
focus: (0,-1/2) (p-distance below vertex on the axis of symmetry)
Directrix: y=1/2 (p-distance above vertex on the axis of symmetry)
see graph below:
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%5E2%2F2%29+