SOLUTION: Find the Standard Form of the equation of the ellipse with the given characteristics and center at the origin. Characteristics: Foci: (plus & minus 5, 0) , Major axis of length 12

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the Standard Form of the equation of the ellipse with the given characteristics and center at the origin. Characteristics: Foci: (plus & minus 5, 0) , Major axis of length 12      Log On


   



Question 771118: Find the Standard Form of the equation of the ellipse with the given characteristics and center at the origin.
Characteristics: Foci: (plus & minus 5, 0) , Major axis of length 12
HELP?!

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the Standard Form of the equation of the ellipse with the given characteristics and center at the origin.
Characteristics: Foci: (plus & minus 5, 0) , Major axis of length 12
***
Given ellipse has a horizontal major axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1, a>b, (h,k)=(x,y) coordinates of center.
For given ellipse:
Given center: (0,0)
Given length of horizontal major axis=12=2a
a=6
a^2=36
c=5 (distance from center to foci)
c^2=25
c^2=a^2-b^2
b^2=a^2-c^2=36-25=11
Equation of given ellipse:
x%5E2%2F36%2By%5E2%2F11=1