SOLUTION: What is the radius of the circle between and tangent to the circles with these equations: (x+1)^2 + (y-7)^2=1 (x-6)^2 + (y-1)^2=1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the radius of the circle between and tangent to the circles with these equations: (x+1)^2 + (y-7)^2=1 (x-6)^2 + (y-1)^2=1      Log On


   

Question 770777: What is the radius of the circle between and tangent to the circles with these equations:
(x+1)^2 + (y-7)^2=1
(x-6)^2 + (y-1)^2=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the radius of the circle between and tangent to the circles with these equations:
(x+1)^2 + (y-7)^2=1
(x-6)^2 + (y-1)^2=1
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circle A with center at (-1,7)
circle B with center at (6,1)
circle C (in-between circle
Radius of circle C=(1/2)(distance between centers of circles A and B minus the sum of their radii)
use distance formula:d=√(x1-x2)^2+(y1-y2)^2)
=√(-1-6)^2+(7-1)/2)=√(49+36)=√85
Radius of circle C=(1/2)(√85-2)≈3.61