Question 770214: y^2-8x-6y+1=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! y^2-8x-6y+1=0
y^2-6y-8x=-1
complete the square
(y^2-6y+9)=-1+8x+9
(y-3)^2=8x+8
(y-3)^2=8(x+1)
This is an equation of a parabola that opens rightward.
Its basic equation: (y-h)^2=4p(x-k), (h,k)=(x,y) coordinates of the vertex.
For given parabola:
vertex:(-1,3)
axis of symmetry: y=3
4p=8
p=2
directrix: x=-3
focus: (1,3)
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