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Question 767627: I need to graph the equation of y=(x+2)^2-1 along with the vertex, focus, axis of symmetry, latus rectum and direction of opening, can you please help me? this lesson is new and I haven't understood that much. My theory is that the vertex is (-2, and 1)? and if -2 is h, then the axis of symmetry is -2, too? I really don't know. Please explain in full details.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! Here is the graph of y=(x+2)^2-1
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vertex is (-2, -1)
axis of symmetry is x = -2
parabola opens upward
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find focus point
y=(x+2)^2-1,***for upward pointing parabola x^2 = 4ay
(4/4)y = (x+2)^2-1
factor the 4 out and we have
4*(1/4)y = (x+2)^2-1
focus is at (-2, -3/4)
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latus rectum is the line through the focus perpendicular to the axis of symmetry, in this case it is the line y = -3/4
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