SOLUTION: the equation of the parabola with focus (0,4) and vertexn(0,0)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: the equation of the parabola with focus (0,4) and vertexn(0,0)      Log On


   

Question 763776: the equation of the parabola with focus (0,4) and vertexn(0,0)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
From 0 to 4 means p+=+4
now use a form: %28x-h%29%5E2+=+4p%28y-k%29......you have h+=+0, k+=+0, p+=+4
Substitute the values:
%28x-0%29%5E2+=+4%2A4%28y-0%29
16y+=+x%5E2
y+=+%281%2F16%29x%5E2

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F16%29x%5E2%29+