SOLUTION: Graph the ellipse and locate the foci ? X^2/64 + y^2/16 = 1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Graph the ellipse and locate the foci ? X^2/64 + y^2/16 = 1      Log On


   



Question 763198: Graph the ellipse and locate the foci ?
X^2/64 + y^2/16 = 1

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the ellipse and locate the foci ?
X^2/64 + y^2/16 = 1
***
Given ellipse has a horizontal major axis with center at (0,0)
Its standard form of equation: x%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2, a>b
For given ellipse:
a^2=64
a=8
b^2=16
b=4
c^2=a^2-b^2=64-16=48
c=√48≈6.93
foci:(0±c,0)=(±6.93,0)=(-6.93,0) and (6.93,0)
see graph below:
y=±(16-x^2/4)^.5