SOLUTION: Hello, I've struggled with conic sections for two months and keep getting the wrong answers. I skipped #s 3 and 4 on circles because those were right. <p> <b>Problem #5: "Find th

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Hello, I've struggled with conic sections for two months and keep getting the wrong answers. I skipped #s 3 and 4 on circles because those were right. <p> <b>Problem #5: "Find th      Log On


   

Question 76154: Hello, I've struggled with conic sections for two months and keep getting the wrong answers. I skipped #s 3 and 4 on circles because those were right.


Problem #5: "Find the foci for the ellipse and sketch a graph of
+x%5E2%2F9%2By%5E2%2F25=1."


Unfortunately, all I got was a foci at +4,0 and -4,0; but I don't know how to graph it.
Answer by checkley75(3666) About Me  (Show Source):

You can put this solution on YOUR website!
x^2/9+y^2/25=1
setting y=0 we get
x^2/9=1
x^2=9
x=+-3
set x=0 we get
y^2/25=1
y^2=25
y=+-5
y^2/25=-x^2/9+1
y^2=25(-x^2/9)+25
y=sqrt(25*-x^2/9+25)
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+sqrt%2825%28-x%5E2%29%2F9+%2B25%29%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = sqrt(25(-x^2)/9 +25)).