SOLUTION: i need help finding the center, coverticies, focis of this equation (x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: i need help finding the center, coverticies, focis of this equation (x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?      Log On


   

Question 753292: i need help finding the center, coverticies, focis of this equation (x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
finding the center, coverticies, focis of this equation:
(x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?
(x+1)^2/16-(y-2)^2/49=1
This is a hyperbola with horizontal transverse axis>
Its standard form of equation:%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1, (a,b)=(x,y) coordinates of center
For given equation:
center: (-1,2)
a^2=16
a=4
b^2=49
b=7
co-vertices:(-1,2±b)=(-1,2±7‚=(-1,9) and (-1,-5)
c^2=a^2+b^2=16+49=65
c=√65≈8.06
foci::(-1,2±c)=(-1,2±8.06‚=(-1,10.06) and (-1,-6.06)