SOLUTION: how would you solve y^2-x+2y+3=0 i am lost and do not know how to do it nor graph it.

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Question 753095: how would you solve y^2-x+2y+3=0 i am lost and do not know how to do it nor graph it.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve y^2-x+2y+3=0
complete the square:
(y^2+2y+1)-1-x+3=0
(y+1)^2=x-2
This is an equation of a parabola that opens rightward with vertex at (2,-1)
Its basic equation: (y-k)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
see graph below:

+graph%28+300%2C+300%2C+-6%2C+10%2C+-10%2C+10%2C+%28x-2%29%5E.5-1%2C-%28x-2%29%5E.5-1%29+