SOLUTION: fine equation of the ellipse which had eccentricity of 3/4 and its equation of directrix is y= +-16/3

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Question 752405: fine equation of the ellipse which had eccentricity of 3/4 and its equation of directrix is y= +-16/3
Answer by lwsshak3(11628) About Me  (Show Source):
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find equation of the ellipse which had eccentricity of 3/4 and its equation of directrix is y= +-16/3
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given ecccentricity,e=3/4
center:(0,0)
ellipse has a vertical major axis:
Its standard form of equation:x%5E2%2Fb%5E2%2By%5E2%2Fa%5E2=1, a>b
ae=directrix=±16/3
a=(16/3)/(3/4)
a=4
a^2=16
c^2=a^2-b^2
e=c/a
c=ae=4*3/4=3
b^2=a^2-c^2=16-9=7
Equation of given ellipse:
x%5E2%2F7%2By%5E2%2F16=1