SOLUTION: what is the focus of the parabola with the equation x^2=48y
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Question 750689
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what is the focus of the parabola with the equation x^2=48y
Answer by
stanbon(75887)
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what is the focus of the parabola with the equation x^2=48y
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Form: (x-0)^2 = 4p(y-0)
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4p = 48
p = 12
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Vertex is at (0,0)
Focus is at (0,0+p) = (0,12)
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Cheers,
Stan H.