SOLUTION: one minor axis vertex is located at (2,-3). Find the other minor axis vertex for the ellipse defined by this equation: (x-2)^2/64 + (y+9)^2/36 =1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: one minor axis vertex is located at (2,-3). Find the other minor axis vertex for the ellipse defined by this equation: (x-2)^2/64 + (y+9)^2/36 =1      Log On


   

Question 749185: one minor axis vertex is located at (2,-3). Find the other minor axis vertex for the ellipse defined by this equation: (x-2)^2/64 + (y+9)^2/36 =1
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
one minor axis vertex is located at (2,-3). Find the other minor axis vertex for the ellipse defined by this equation: (x-2)^2/64 + (y+9)^2/36 =1
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center at (2,-9)
semi-minor axis = 6 in a y direction
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Since (2,-3) is 6 above the center;
Other vertex is 6 below (2,-9) at (2,-14)
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Cheers,
Stan H.
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