SOLUTION: 5y^2-4x^2=20 What is the vertex form? What is the type of conic? What is the direction?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 5y^2-4x^2=20 What is the vertex form? What is the type of conic? What is the direction?      Log On


   

Question 748240: 5y^2-4x^2=20
What is the vertex form?
What is the type of conic?
What is the direction?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

5y%5E2-4x%5E2=20+

5y%5E2%2F20-4x%5E2%2F20=20%2F20+
y%5E2%2F4-x%5E2%2F5=1+.........the vertex form %28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2;

the type of conic: hyperbola with the vertical transverse axis, h=0, k=0, a%5E2=4, and b%5E2=5
a+=+2, the distance from the center to the vertices of the hyperbola in the vertical direction (up and down from the center). This is called the transverse axis.
The branches of the hyperbola open up/down.