Question 747685: What is the focus, directrix, and the equation of the axis of symmetry for y = 1/20x2
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! What is the focus, directrix, and the equation of the axis of symmetry
for y = 1/20x2
(x-0)^2 = 20(y-0)
4p = 20
p = 5
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Vertex: (0,0)
axis of symmetry: x = 0
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directrix: y = -5
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Focus: (0,5)
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Cheers,
Stan H.
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