SOLUTION: find an equations for the conic section that satisfies the given conditions. Hyperbola, foci (2,0), (2,8) asymptose y=3+1/2x y=5-1/2x

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find an equations for the conic section that satisfies the given conditions. Hyperbola, foci (2,0), (2,8) asymptose y=3+1/2x y=5-1/2x       Log On


   



Question 746309: find an equations for the conic section that satisfies the given conditions. Hyperbola, foci (2,0), (2,8) asymptose y=3+1/2x y=5-1/2x

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find an equations for the conic section that satisfies the given conditions. Hyperbola, foci (2,0), (2,8) asymptose y=3+1/2x y=5-1/2x
***
Given hyperbola has a vertical transverse axis (y-coordinates of foci change but x-coordinates do not)
Its standard form of equation: %28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center-
..
center: (2,4)
..
c=4 (distance from center to foci
c^2=16
..
given slopes of asymptotes=±1/2=a/b (for hyperbolas with vertical transverse axis)
a/b=1/2
b=2a
..
c^2=a^2+b^2
c^2=a^2+4a^2=5a^2
5a^2=16
a^2=16/5
a=4/√5
b^2=64√5
..
Equation of given hyperbola:
5%28y-4%29%5E2%2F16-5%28x-2%29%5E2%2F64=1