SOLUTION: help me please!
a dog trainer has 80 ft of fencing that will be used to create a rectangular work area for dogs . if the trainer wants to enclose an area of 300 ft what will be
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a dog trainer has 80 ft of fencing that will be used to create a rectangular work area for dogs . if the trainer wants to enclose an area of 300 ft what will be
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Question 741152: help me please!
a dog trainer has 80 ft of fencing that will be used to create a rectangular work area for dogs . if the trainer wants to enclose an area of 300 ft what will be the dimensions of the work area
You can put this solution on YOUR website! a dog trainer has 80 ft of fencing that will be used to create a rectangular work area for dogs . if the trainer wants to enclose an area of 300 ft^2 what will be the dimensions of the work area
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Let length be "x"
Then width = (80-2x)/2 = 40-x
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Equation:
Area = length*width
x(40-x) = 300
-x^2+40x-300 = 0
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x^2 -40x +300 = 0
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Factor:
(x-30)(x-10) = 0
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x = 10 or x = 30
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Length = 10 ft
width = (80-2*10)/2 = 30 ft
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Cheers,
Stan H.
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