SOLUTION: can you help me with question? this is from a hand out. Find the center and radius of x^2+y^2-x+2y-3=0 I figured r=square root 17/2 and c=(0.5,-1)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: can you help me with question? this is from a hand out. Find the center and radius of x^2+y^2-x+2y-3=0 I figured r=square root 17/2 and c=(0.5,-1)       Log On


   

Question 74046: can you help me with question?
this is from a hand out.
Find the center and radius of x^2+y^2-x+2y-3=0
I figured r=square root 17/2
and c=(0.5,-1)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2-x%2B2y-3=0
x%5E2-x%2By%5E2%2B2y=3
x%5E2-x%2B1%2F4%2By%5E2%2B2y%2B1=3%2B1%2F4%2B1
%28x-1%2F2%29%5E2%2B%28y%2B1%29%5E2=%2817%2F4%29%5E2
So you are right the center is (0.5,-1) with a radius of sqrt%2817%29%2F2