SOLUTION: I have a question on Hyperbolas. This is what I think I know so far, Orientation=Horizontal, Center=(0,0), a=7, b=5,c=8.602 The equation is {{{(x^2)/(25)-(y^2)/(49)=1}}}

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I have a question on Hyperbolas. This is what I think I know so far, Orientation=Horizontal, Center=(0,0), a=7, b=5,c=8.602 The equation is {{{(x^2)/(25)-(y^2)/(49)=1}}}      Log On


   

Question 735422: I have a question on Hyperbolas. This is what I think I know so far, Orientation=Horizontal, Center=(0,0), a=7, b=5,c=8.602 The equation is %28x%5E2%29%2F%2825%29-%28y%5E2%29%2F%2849%29=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E2%29%2F%2825%29-%28y%5E2%29%2F%2849%29=1
This is an equation of a hyperbola with horizontal transverse axis.
Its standard form:%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1,(h,k)=(x,y) coordinates of center.
For given equation:
center:(0,0)
a^2=25
a=5
b^2=49
b=7
c^2=a^2+b^2=25+49=74
c=√74≈8.60
You got everything right except a and b which you had in reverse.
For hyperbolas, a and b don't change positions like in ellipses
For hyperbolas with vertical transverse axis, the y-term is placed ahead of the x-term, but a and b remain in the same position as that for a hyperbola with horizontal transverse axis