SOLUTION: Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola focus (3,8) vertex (3,2)

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Question 732373: Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola
focus (3,8)
vertex (3,2)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola
focus (3,8)
vertex (3,2)
***
This is a parabola that opens upward.
Its basic equation: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex.
vertex: (3,2)
axis of symmetry: x=3
p=6 (distance from vertex to focus on the axis of symmetry
4p=24
Equation: (x-3)^2=24(y-2)
see graph below:
+graph%28+300%2C+300%2C+-10%2C10%2C+-10%2C+10%2C+%28x%5E2-6x%2B57%29%2F24%29+