SOLUTION: find the standard equation for the parabola and graph it focus =-1,3 vertex =-1,2

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Question 732109: find the standard equation for the parabola and graph it
focus =-1,3 vertex =-1,2

Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
You could literally use the distance formula and derive the equation. You would need the directrix along with the given focus. The directrix is the line, y=1 [do you know why?]

A parabola is the set of points equally distant from ______________ and ____________. The vertex is exactly between them. [You should fill in those two blanks.]

A good picture or representative graph would help. Maybe you can draw one, label some parts and points, and write the needed equation to start. The point, any general point, on the parabola will be (x, y). The coordinate for any fitting point on the directrix would be (x, 1). You obviously have the focus coordinates of (-1, 3). This all should be enough for you to derive the equation for this parabola, which is often well shown in most of the textbooks.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
given: vertex (-1,2 ) and focus (-1,3).
find: the standard equation for the parabola and graph it
the x-coordinates of the vertex and focus are the same, they are one of top of the other,
so this is a regular vertical parabola, where the x part is squared
Since the vertex is below the focus, this is a right-side up parabola and p+is positive.
Since the vertex and focus are 3+-2+=+1 units apart, then p+=+1.
that's all we need for equation:
%28x+-h%29%5E2+=+4p%28y+-+k%29
%28x+%2B1%29%5E2+=+4%281%29%28y-2%29
%28x+%2B1%29%5E2+=+4%28y-2%29....vertex form
the standard form of a parabola in the form of
y+=+a+x%5E2+%2B+b+x+%2B+c
so, expand and solve %28x+%2B1%29%5E2+=+4%28y-2%29 for y
x%5E2%2B2x+%2B1+=+4y-8
x%5E2%2B2x+%2B1%2B8+=+4y
x%5E2%2B2x+%2B9+=+4y
x%5E2%2F4%2B2x%2F4+%2B9+%2F4=+y
y=%281%2F4%29x%5E2%2B%281%2F2%29x+%2B2.25

graph: