SOLUTION: which conic section is 3(x+5)^2+3y-15=0

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Question 730511: which conic section is 3(x+5)^2+3y-15=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
which conic section is
3(x+5)^2+3y-15=0
3(x^2+10x+25)+3y-15=0
3x^2+30x+75+3y-15=0
3x^2+30x+3y=-60
x^2+10x+y=-20
complete the square:
(x^2+10x+25)+y=-20+25
(x+5)^2+y=5
y=-(x+5)^2+5
This is a parabola that opens down with vertex at (-5,5)