SOLUTION: An ellipse has a center (3, 2) and foci are located at (0, 2) and (6, 2). The length of the major axis is 12 units. Fill in the missing denominators for the equation of the ellipse

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: An ellipse has a center (3, 2) and foci are located at (0, 2) and (6, 2). The length of the major axis is 12 units. Fill in the missing denominators for the equation of the ellipse      Log On


   



Question 730251: An ellipse has a center (3, 2) and foci are located at (0, 2) and (6, 2). The length of the major axis is 12 units. Fill in the missing denominators for the equation of the ellipse. (x-3)^2/? + (y-2)^2/?=1.
Answer by lwsshak3(11628) About Me  (Show Source):
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An ellipse has a center (3, 2) and foci are located at (0, 2) and (6, 2). The length of the major axis is 12 units. Fill in the missing denominators for the equation of the ellipse.
(x-3)^2/? + (y-2)^2/?=1
***
given length of major axis=12=2a
a=6
a^2=36
c=3 (distance from center to foci)
c^2=9
c^2=a^2-b^2
b^2=a^2-c^2=36-9=27
Equation of given ellipse:
%28x-3%29%5E2%2F36+%2B+%28y-2%29%5E2%2F27=1