SOLUTION: -2x^2+y^2+8x+6y-3=0

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Question 726222: -2x^2+y^2+8x+6y-3=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
-2x^2+y^2+8x+6y-3=0
-2x^2+8x+y^2+6y-3=0
complete the square:
-2(x^2-4x+4)+(y^2+6y+9)=3-8+9
-2(x-2)^2+(y+3)^2=4
-2(x-2)^2+(y+3)^2=4
-(x-2)^2/2+(y+3)^2/4=1
%28y%2B3%29%5E2%2F4-%28x-2%29%5E2%2F2=1
This is an equation of a hyperbola with vertical transverse axis with center at (2,-3)
Its standard form: %28y-k%29%5E2%2Fa%5E2-%28h-k%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center