SOLUTION: Given f(x)=4x^2+3x-1 What are the zeroes in the function I Only got as fas as 0=4(x^2+3x-1)

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Question 725496: Given f(x)=4x^2+3x-1 What are the zeroes in the function
I Only got as fas as 0=4(x^2+3x-1)
Answer by Alan3354(69443) About Me  (Show Source):
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Given f(x)=4x^2+3x-1 What are the zeroes in the function
I Only got as fas as 0=4(x^2+3x-1)
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0=4(x^2+3x-1) is not right. You didn't divide all 3 terms by 4.
4x^2+3x-1 = 0
(4x - 1)*(x + 1) = 0
x = -1
x = 1/4