SOLUTION: Write the standard form equation of an ellipse: Vertices: (5,-3) (-3,-3) Co-vertices: (1,0), (1, -6) I know how to find the standard form with only two endpoints rather than f

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write the standard form equation of an ellipse: Vertices: (5,-3) (-3,-3) Co-vertices: (1,0), (1, -6) I know how to find the standard form with only two endpoints rather than f      Log On


   



Question 713388: Write the standard form equation of an ellipse:
Vertices: (5,-3) (-3,-3)
Co-vertices: (1,0), (1, -6)
I know how to find the standard form with only two endpoints rather than four.
Thanks for your help!

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the standard form equation of an ellipse:
Vertices: (5,-3) (-3,-3)
Co-vertices: (1,0), (1, -6)
I know how to find the standard form with only two endpoints rather than four.
Thanks for your help!
**
Given data shows ellipse has a horizontal major axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1, a>b, (h,k)=(x,y) coordinates of center.
x-coordinate of center= (5+(-3))/2=2/2=1 (midpoint formula)
y-coordinate of center=-3
center:(1,-3)
length of horizontal major axis=8 (-3 to 5)=2a
a=4
a^2=16
length of minor axis (co-vertices)=6 (0 to 6)=2b
b=3
b^2=9
..
Equation of given ellipse:
%28x-1%29%5E2%2F16%2B%28y%2B3%29%5E2%2F9=1