SOLUTION: Trying to graph the parabola y=-3(x+7)^2-8 and get vertex of (-7, -8) with another point of (0, -155) which seems odd. Is this correct? In order to graph, should I try x=somethin

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Trying to graph the parabola y=-3(x+7)^2-8 and get vertex of (-7, -8) with another point of (0, -155) which seems odd. Is this correct? In order to graph, should I try x=somethin      Log On


   

Question 712913: Trying to graph the parabola y=-3(x+7)^2-8 and get vertex of (-7, -8) with another point of (0, -155) which seems odd. Is this correct? In order to graph, should I try x=something other than "0"??
Thanks
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
y=-3(x+7)^2-8
y=-3(x^2+14x+49)-8
y=--3x^2-42x-147-8
y=-3x^2-42x-155
+graph%28+300%2C+200%2C+-26%2C+5%2C+-160%2C+10%2C+-3x%5E2+-42x-155%29+