SOLUTION: how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation x=(1/16)(y-7)^2-5

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation x=(1/16)(y-7)^2-5      Log On


   

Question 691455: how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation
x=(1/16)(y-7)^2-5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation
x=(1/16)(y-7)^2-5
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Since the vertex is at (-5,7),
axis of symmetry: y = 7
Focus and Directrix ????
4p = 1/16
p = 1/64
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Focus: (-5+(1/64),7)
Directix: x = -5-(1/64)
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Cheers,
Stan H.
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