SOLUTION: Find the equation of the ellipse with the given conditions. Center (1,1), vertex (1,3), passing through (0,0). I need your help.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the equation of the ellipse with the given conditions. Center (1,1), vertex (1,3), passing through (0,0). I need your help.      Log On


   



Question 689855: Find the equation of the ellipse with the given conditions.
Center (1,1), vertex (1,3), passing through (0,0).
I need your help.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the ellipse with the given conditions.
Center (1,1), vertex (1,3), passing through (0,0).
**
This is an ellipse with vertical major axis.
Its standard form of equation:+%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, a>b, (h,k)=(x,y) coordinates of center
For given ellipse:
center: (1,1)
length of major axis=4=2a
a=2
a^2=4
plug in coordinates of given point on ellipse: (0,0)
(x-1)^2/b^2+(y-1)^2/4=1
(0-1)^2/b^2+(0-1)^2/4=1
1/b^2+1/4=1
1/b^2=3/4
b^2=4/3
Equation of given ellipse:
3%28x-1%29%5E2%2F4+%2B%28y-1%29%5E2%2F4=1