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Question 688624: (y+2)^2=-8(x-1)
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! (y+2)^2=-8(x-1)
This is an equation of a parabola that opens leftwards.
Its standard form: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex.
For given equation:
vertex:(1,-2)
axis of symmetry: y=-2
4p=8
p=2
focus:(-1,-2) (p-distance to the left of the vertex on the xis of symmetry)
directrix:x=3 (p-distance to the right of the vertex on the xis of symmetry)
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