Question 686364: e=square root of 5/2 ; major axis along the x-axis ; minor axis along the line x-5=0 ; passes through the point 5,2 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! e=square root of 5/2 ; major axis along the x-axis ; minor axis along the line x-5=0 ; passes through the point 5,2
I will assume e=sqrt of 2/5 instead of 5/2 (0 < e < 1 for ellipses)
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This is an ellipse with horizontal major axis.
Its standard form of equation: , a>b, (h,k)=(x,y) coordinates of center
For given ellipse:
center: (5,0)
plug in coordinates of center and given point (5,2)
(5-5)^2/a^2+(2-0)^2/b^2=1
4/b^2=1
b^2=4
..
eccentricity=√(2/5)=√(a^2-b^2)/a
square both sides
2/5=(a^2-b^2)/a^2
2a^2=5a^2-5b^2
3a^2=5b^2
a^2=5b^2/3
a^2=20/3
..
Equation:
(