SOLUTION: Graph the ellipse (x+3)^2/16 + (y-3)^2/4 Here is what I have for the info Center: (-3,3) vertex1: (1,3) vertex2: (-7,3) focus1: (-3+2sqrt3,3) focus2: (-3-2sqrt3,3)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Graph the ellipse (x+3)^2/16 + (y-3)^2/4 Here is what I have for the info Center: (-3,3) vertex1: (1,3) vertex2: (-7,3) focus1: (-3+2sqrt3,3) focus2: (-3-2sqrt3,3)       Log On


   



Question 682157: Graph the ellipse
(x+3)^2/16 + (y-3)^2/4
Here is what I have for the info
Center: (-3,3)
vertex1: (1,3)
vertex2: (-7,3)
focus1: (-3+2sqrt3,3)
focus2: (-3-2sqrt3,3)
is this correct? and what does it look like on a graph?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the ellipse
(x+3)^2/16 + (y-3)^2/4
Here is what I have for the info
Center: (-3,3)
vertex1: (1,3)
vertex2: (-7,3)
focus1: (-3+2sqrt3,3)
focus2: (-3-2sqrt3,3)
is this correct? and what does it look like on a graph?
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Plot the center so you know where it is.
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Plot vertex1 and vertex 2 to the left and right of the center.
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Since the semi-minor axis is sqrt(4) = 2 the high and the
low point of the curve are at (-3,5) and (-3,1). Plot those points.
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Draw your graph thru those points.
Cheers,
Stan H.