SOLUTION: it says, "Identify the curve and find the characteristics listed. then sketch the curve." (x-3)^2/9 + (y+3)^2/16= 1 center vertices foci y^2/16 - x^2/9 = 1 center asymptotes

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: it says, "Identify the curve and find the characteristics listed. then sketch the curve." (x-3)^2/9 + (y+3)^2/16= 1 center vertices foci y^2/16 - x^2/9 = 1 center asymptotes      Log On


   



Question 668469: it says, "Identify the curve and find the characteristics listed. then sketch the curve."
(x-3)^2/9 + (y+3)^2/16= 1 center vertices foci
y^2/16 - x^2/9 = 1 center asymptotes foci
hopefully someone can help me


Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi, Standard Forms are the quidelines
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center
and ±sqrt%28a%5E2-b%5E2%29are the foci distances from center: a > b
(x-3)^2/9 + (y+3)^2/16= 1 C(3,-3), V(0,-3)& V(6,-3), V(3,1) &(3,-7),
F(3, -3 + sqrt(7)) and F(3,-3-sqrt(7))

Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 with C(h,k) and vertices 'b' units up and down from center, 2b the length of the transverse axis
Foci sqrt%28a%5E2%2Bb%5E2%29units units up and down from center, along x = h
& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a