SOLUTION: The question states, "Identify the curve and find the characteristics listed. then sketch the curve." x^2 + (y-4)^2= 64 center radius (x+3)^2 + (y+6)^2 = 49 center raidus

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The question states, "Identify the curve and find the characteristics listed. then sketch the curve." x^2 + (y-4)^2= 64 center radius (x+3)^2 + (y+6)^2 = 49 center raidus       Log On


   

Question 668467: The question states, "Identify the curve and find the characteristics listed. then sketch the curve."
x^2 + (y-4)^2= 64 center radius
(x+3)^2 + (y+6)^2 = 49 center raidus eccentricity


someone help! the book doesnt really explain how to do this?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, Standard form is the quideline

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius

x^2 + (y-4)^2= 64 center(0,4) radius = 8

 (x+3)^2 + (y+6)^2 = 49 center(-3,-6) radius = 7  eccentricity = 0



·	At eccentricity = 0 we get a circle

·	For 0 < eccentricity < 1 we get an ellipse  e+=+sqrt%28a%5E2-b%5E2%29%2Fa

·	for eccentricity = 1 we get a parabola

·	for eccentricity > 1 we get a hyperbola   e+=+sqrt%28a%5E2%2Bb%5E2%29%2Fa

·	for infinite eccentricity we get a line