SOLUTION: To the nearest foot per second , what is the maxium safe landing speed ? L = Length s = speed The equation is L = 0.5s^2 + -4s + 10 How do I complete this if L = 1,500 ?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: To the nearest foot per second , what is the maxium safe landing speed ? L = Length s = speed The equation is L = 0.5s^2 + -4s + 10 How do I complete this if L = 1,500 ?      Log On


   



Question 658223: To the nearest foot per second , what is the maxium safe landing speed ?
L = Length s = speed
The equation is L = 0.5s^2 + -4s + 10
How do I complete this if L = 1,500 ?

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Take out the L and replace it with 1500.





Solve the quadratic for

John

My calculator said it, I believe it, that settles it
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