SOLUTION: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
And:
What is the equation of the axis of symmetry of the parabola whose equation
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
And:
What is the equation of the axis of symmetry of the parabola whose equation
Log On
Question 658044: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
And:
What is the equation of the axis of symmetry of the parabola whose equation is 2(y - 2) = (x + 3)2?
x = -3
x = 3
x = 0
y = -2
y = 2 Found 2 solutions by stanbon, ewatrrr:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
-----
Form: (x-h)^2/a^2 + (y-k)/b^2 = 1
h = 6, k = -1 ; a = 6 ; b = 3
Equation:
(x-6)^2/36 + (y+1)/9 = 1
=============================
And:
What is the equation of the axis of symmetry of the parabola whose equation is 2(y - 2) = (x + 3)2?
Vertex is at (-3,2)
Axis of symmetry is x = -3
==============================
Cheers,
Stan H.
===============
x = -3
x = 3
x = 0
y = -2
y = 2
Hi,
Standard Form of an Equation of an Ellipse is
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center
(0, -1) and (12, -1), C(6,-1) and minor axis of length 6. b = 3
the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry x = -3 is the Line of Symmetry