SOLUTION: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6 And: What is the equation of the axis of symmetry of the parabola whose equation

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6 And: What is the equation of the axis of symmetry of the parabola whose equation       Log On


   



Question 658044: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
And:
What is the equation of the axis of symmetry of the parabola whose equation is 2(y - 2) = (x + 3)2?
x = -3
x = 3
x = 0
y = -2
y = 2

Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
-----
Form: (x-h)^2/a^2 + (y-k)/b^2 = 1
h = 6, k = -1 ; a = 6 ; b = 3
Equation:
(x-6)^2/36 + (y+1)/9 = 1
=============================
And:
What is the equation of the axis of symmetry of the parabola whose equation is 2(y - 2) = (x + 3)2?
Vertex is at (-3,2)
Axis of symmetry is x = -3
==============================
Cheers,
Stan H.
===============
x = -3
x = 3
x = 0
y = -2
y = 2

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center
(0, -1) and (12, -1), C(6,-1) and minor axis of length 6. b = 3
%28x-6%29%5E2%2F6%5E2+%2B+%28y%2B1%29%5E2%2F3%5E2+=+1+

the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry
%28y+-+2%29+=+%281%2F2%29%28x+%2B+3%29%5E2 x = -3 is the Line of Symmetry