SOLUTION: Find slopes of the asymptotes of the hyperbola with the equation 36 = 9x squared - 4y squared

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Question 636911: Find slopes of the asymptotes of the hyperbola with the equation
36 = 9x squared - 4y squared
Answer by lwsshak3(11628) About Me  (Show Source):
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Find slopes of the asymptotes of the hyperbola with the equation
36 = 9x squared - 4y squared
**
rewrite given equation
9x^2-4y^2=36
divide by 36
x^2/4-y^2/9=1
This is a hyperbola with horizontal transverse axis.
Its standard form: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1
For given equation:x%5E2%2F4-y%5E2%2F9=1
a^2=4
a=√4=2
b^2=9
b=√9=3
slopes of asymptotes for given hyperbola=±b/a=±3/2