SOLUTION: find the center and radius of the circle 4x^2 + 4y^2 - 9 =0

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Question 636875: find the center and radius of the circle
4x^2 + 4y^2 - 9 =0
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of the circle is
%28x-x0%29%5E2%2B%28y-y0%29%5E2=R%5E2
Where (x0, y0) is the center, R is the radius of the circle
4x%5E2+%2B+4y%5E2+-+9+=0
4x%5E2+%2B+4y%5E2+=9divide by 4
x%5E2+%2B+y%5E2+=9%2F4
Hence, (0,0) is the center, R=3/2 is the radius