SOLUTION: find the vertex of y=x^2-1
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Question 634994
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find the vertex of y=x^2-1
Answer by
stanbon(75887)
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find the vertex of y=x^2-1
a = 1 ; b = 0 ; c = -1
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vertex occurs at x = -b/(2a) = -0/(2) = 0
f(0) = -1
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Vertex: (0,-1)
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Cheers,
Stan H.
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