You can put this solution on YOUR website! Standard form of parabola: (y-k)^2=-4p(x-h), with (h,k) being the (x,y) coordinates
of the vertex. This parabola opens leftwards and has a horizontal axis of symmetry.
For given problem:
Axis of symmetry = x-axis or y=0
p=distance from vertex to focus on axis of symmetry=4
center (0, 0)
Equation:
See graph below as a visual check on the equation
Hi,
parabola with the vertex at the origin and focus at (-4,0), p = 4
16x = y^2
the vertex form of a Parabola opening right(a>0) or left(a<0),
where(h,k) is the vertex and y = k is the Line of Symmetry
The standard form is , where the focus is (h +p,k)
