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Question 629356:
25 + 4x² = -20x
discriminant
how do you find the determinant then the number of rational, irrational or complex roots??
Found 2 solutions by solver91311, Edwin McCravy: Answer by solver91311(24713) (Show Source): Answer by Edwin McCravy(20059) (Show Source):
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25 + 4x² = -20x
how do you find the determinant then the number of rational, irrational or complex roots??
The word is "discriminant", not "determinant".
First you get the quadratic equation in descending order with 0
on the right.
25 + 4x² = -20x
4x² + 20x + 25 = 0
Compare that to the general quadratic equation:
ax² + bx + c = 0
If you remember the quadratic formula,
then you already know the discriminant formula because it is
what is under the aquare root part of the quadratic formula.
Discriminant = b² - 4ac
Comparing your equation to the general quadratic equation,
a = 4, b = 20, c = 25
Substitute in the discriminant formula:
Discriminant = b² - 4ac
Discriminant = (20)² - 4(4)(25)
Discriminant = 400 - 400
Discriminant = 0
The rules are
1. If the discriminant is positive there are 2 real roots
A. If the discriminant is a perfect square, both roots are rational
B. If the discriminant is not a perfect square, both roots are irrational.
2. If the discriminant is negative, there are 2 conjugate complex roots.
3. If the discriminant is 0, there is just one real rational root.
Your problem is case 3, so there is one real rational root.
Edwin
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