SOLUTION: Write an equation of the line tangent to the given circle at the given point. {{{ x^2+y^2=52 }}} (-4,6)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write an equation of the line tangent to the given circle at the given point. {{{ x^2+y^2=52 }}} (-4,6)      Log On


   

Question 624448: Write an equation of the line tangent to the given circle at the given point.
+x%5E2%2By%5E2=52+ (-4,6)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Note: Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius



Write an equation of the line tangent to the given circle at the given point.

+x%5E2%2By%5E2=52+ (-4,6)  || Center of the circle is (0,0)

(-4,6)

(0,0) m = 6/-4 Green Line has slope m = -3/2, 

the Line Tangent at (-4,6) would be perpendicular to the Green with m = 2/3

 y = (2/3)x + b

 6 = -8/3 + b,  

  26/3 = b ,     y = (2/3)x + 26/3