Question 624382: Graph the equation (I don't know how to find them)
Identify the vertices of the ellipse.
Identify the co-vertices of the ellipse.
Identify the foci of the ellipse.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Graph the equation (I don't know how to find them)
2x^2+50y^2=50
Identify the vertices of the ellipse.
Identify the co-vertices of the ellipse.
Identify the foci of the ellipse.
**
2x^2+50y^2=50
x^2/25+y^2=1
This is an equation of an ellipse with horizontal major axis with center at the origin (0,0)
Its standard form of equation: x^2/a^2+y^2/b^2=1, a>b
center:(0,0)
a^2=25
a=5
Vertices: (0±a,0)=(0±5,0)=(-5,0) and (5,0)
..
b^2=1
b=1
co-vertices: (0,0±b)=(0,0±1)=(0,-1) and (0,1)
..
c^2=a^2-b^2=25-1=24
c=√24≈4.9
Foci: (0±c,0)=(0±4.9,0)=(-4.9,0) and (4.9,0)
see graph below:
y=±(1-x^2/25)^.5
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