SOLUTION: Give the Particulars if y^2 = -16x x^2 + 8y = 0 2y^2 = -3x

 

Hi,  

y^2 = -16x  V(0,0), line of symmetry y = 0, focus (-4,0) directrix x = 4

x^2 = -8y    V(0,0), line of symmetry x = 0, focus (0,-2) directrix y = 2

y^2 = -3/2x V(0,0), line of symmetry y = 0, focus (-3/8,0) directrix x = 3/8 



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the vertex form of a Parabola opening Up(a>0) or Down(a<0),  where(h,k) is the vertex and line of symmetry is x = h

The standard form is , where  the focus is (h,k + p)



the vertex form of a Parabola opening Right(a>0) or Left(a<0),  where(h,k) is the vertex and line of symmetry is y = k

The standard form is , where  the focus is (h +p,k )