SOLUTION: determine the shape of the graph represented by this equation: x^2+4y^2+12x-32y+96=0

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Question 620834: determine the shape of the graph represented by this equation: x^2+4y^2+12x-32y+96=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

x^2+4y^2+12x-32y = 96

(x+6)^2 + (y-16)^2 = 96 - 36 - 256 = 196

%28x%2B6%29%5E2+%2B+%28y-16%29%5E2+=+14%5E2  a circle  C(-6,16) and r = 14