SOLUTION: (x+3)^2/16-y^2/9=1 conic center foci graph

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Question 613637: (x+3)^2/16-y^2/9=1
conic
center
foci
graph
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

%28x%2B3%29%5E2%2F16-y%5E2%2F9=1

Hyperbola opening right and left, C(-3,0) Vertices(-7,0) & (1,0)

 sqrt(16+9) = sqrt(25)= 5  Foci(-8,0) and (2,0)