SOLUTION: find the equation of the ellipse with the following properties. x-intercepts (5,0) and (-5,0); y-intercepts (0,3) and (0,-3)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the equation of the ellipse with the following properties. x-intercepts (5,0) and (-5,0); y-intercepts (0,3) and (0,-3)      Log On


   



Question 612542: find the equation of the ellipse with the following properties.
x-intercepts (5,0) and (-5,0); y-intercepts (0,3) and (0,-3)

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form for the equation of an ellipse is
%28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1
Since the intercepts are on the ellipse in question, they must fit the equation. Substituting (5, 0) into this equation we get:
%285-h%29%5E2%2Fa%5E2+%2B+%280-k%29%5E2%2Fb%5E2+=+1
which simplifies to:
%2825-10h%2Bh%5E2%29%2Fa%5E2+%2B+k%5E2%2Fb%5E2+=+1
Subtracting k%5E2%2Fb%5E2 from each side:
%2825-10h%2Bh%5E2%29%2Fa%5E2+=+1+-+k%5E2%2Fb%5E2
Multiplying by a%5E2:
25-10h%2Bh%5E2+=+a%5E2%281+-+k%5E2%2Fb%5E2%29

Substituting (-5, 0) into %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1 and following the same steps as above we end up with:
25%2B10h%2Bh%5E2+=+a%5E2%281+-+k%5E2%2Fb%5E2%29

Since 25-10h%2Bh%5E2 and 25%2B10h%2Bh%5E2 are both equal to a%5E2%281+-+k%5E2%2Fb%5E2%29, they must be equal to each other:
25-10h%2Bh%5E2+=+25%2B10h+%2Bh%5E2
We can solve this for h. Subtracting 25 and h%5E2 and adding 10h we get:
0 = 20h
Dividing by 20:
0 = h

Using (0, 3) and (0, -3) and logic just like the above we can find that k = 0.

This makes the center of the ellipse (0, 0).

Since the center, (5, 0) and (-5, 0) are all on the x-axis, the given points are not just the intercepts, they are the vertices on the major axis of the ellipse. This means the "a" is 5.

Since the center, (0, 3) and (-5, 0) are all on the y-axis, the given points are not just the intercepts, they are the vertices on the minor axis of the ellipse. This means the "b" is 3.

With the center, a and b we can now write the equation:
%28x-0%29%5E2%2F5%5E2+%2B+%28y-0%29%5E2%2F3%5E2+=+1
which simplifies to:
x%5E2%2F25+%2B+y%5E2%2F9+=+1